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Ways to stay anonymous:

1. Don't cash the ticket.  Instead, frame it with one of the numbers obscured, and hang it in your office. 
2. Give it to someone you can trust, like me to cash in.

Author Topic: Want to remain anonymous, when you win the powerball?  (Read 43593 times)

Offline churnbabychurn

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Re: Want to remain anonymous, when you win the powerball?
« Reply #100 on: January 11, 2016, 12:54:27 PM »
sorry to be mean but your opinion is wrong. Its straight math.
You can be mean don't worry, I can take it.

Offline JamesIV

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Re: Want to remain anonymous, when you win the powerball?
« Reply #101 on: January 11, 2016, 12:56:38 PM »
I'm in

Offline elit

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Offline teetle

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Re: Want to remain anonymous, when you win the powerball?
« Reply #103 on: January 11, 2016, 01:34:32 PM »
Can u plz add me in.

Offline RefuaFan

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Re: Want to remain anonymous, when you win the powerball?
« Reply #104 on: January 11, 2016, 01:51:46 PM »

Not convinced.
Each individual ticket has 1 in 290 mm possibility of winning. Buying two tickets dosnt split the 290 in half.

(It's more like rubah deleisa kamon, not more chances. Just more options.)

All jmho

Here, I'll show you:

1 ticket = 1/292mil chance... = 0.000000003424657534246575% chance of winning (See Dan's comments)
2 tickets = 2/292mil chance.. = 0.000000006849315068493151% chance of winning (See Dan's comments)

Just to show the calculator's background thinking for you:
  0.000000003424657534246575
+0.000000003424657534246575
___________________________
=0.000000006849315068493150

EDIT: Also, 292mil/2 = 146mil. So do 2 tickets split the 292 in half?

2 tickets = 2/292mil chance.. = 0.000000006849315068493151% chance of winning (See Dan's comments)
292mil/2 = 146mil.
1/146mil = 0.000000006849315068493151% chance of winning (See Dan's comments), the same as 2/292mil.


You see that there is a 0.000000000000000000001 difference between adding and multiplying. Either the calculator dropped that off (because see Dan's comments), or, more likely, the discrepancy didn't work out with decimals, sort of like trying to divide 1 by 3 on a calculator (it will say 0.333333333, which will still leave it just under 1 when multiplied times 3. The decimal version of a number sometimes isn't as accurate as the fraction version of the number, i.e. 1/3).

now let's jump the math up to 10 tickets.

1 ticket = 1/292mil chance........ = 0.000000003424657534246575% chance of winning (See Dan's comments)
10 tickets = 10/292mil chances.. = 0.00000003424657534246575% chance of winning (See Dan's comments)

Just for clarity, let's double check that with the number you get from adding the chances from 1 ticket 10 times.

  0.000000003424657534246575
  0.000000003424657534246575
  0.000000003424657534246575
  0.000000003424657534246575
  0.000000003424657534246575
  0.000000003424657534246575
  0.000000003424657534246575
  0.000000003424657534246575
  0.000000003424657534246575
+0.000000003424657534246575
___________________________
=0.00000003424657534246575% chance of winning (See Dan's comments)
(Had to switch to scientific calculator to successfully copy+paste the number 10 times and maintain it's total integrity. Standard calculator cut off some numbers).
You notice that it dropped a decimal point.

And what about multiplying the chance from 1 ticket by 10?

10 x 0.000000003424657534246575
....=0.00000003424657534246575  % chance of winning (See Dan's comments)

Notice that it has stayed the same numbers as the adding version, and again, it simply dropped a decimal. So in jumps of ten, the math from adding the number is the same as multiplying the number. Now, here's what seems to get people arguing. Is 10/292mil really the same as 1/29.2mil? Let's find out!

10/292mil = 0.00000003424657534246575% chance of winning (See Dan's comments)
1/29.2mil = 0.00000003448275862068966% chance of winning (See Dan's comments)
Just to be clear, in math, you can often cut down the number on top of the dividing sign, and do the same thing to the number on the bottom half of the dividing sign. It still maintains the integrity of the number in most (but not all) cases.  So 2/4 = 1/2 (cut both by 2 AKA in half), 4/8 also = 1/2 (cut both by 4 AKA in quarter), and 5/35 = 1/7 (cut both by 5, AKA in fifths).
So with fractions, it makes sense to say that 10/292mil = 1/29.2mil. You're just cutting both sides by 10, AKA tenths.

As you can see, whether adding or multiplying, the chances for the ticket are almost exactly the same. And the chances shown by doing the numbers out of 292mil or cutting it down to smaller numbers like 29.2mil when doing blocks of 10, 100, 1000, etc. (See Zkpncs48's comment) are almost the same. Sure, the 1 vs. 10 example is off by a couple hundred billionths (the name of the decimal spot where the 1/29.2mil and 10/292mil start to vary), but see Dan's comments about statistical significance. For anyone determining their chances, the numbers are basically the same. I'll let someone else post out the numbers for 100, 1000 etc. amounts of tickets.

TL;DR = See Dan's comments.

« Last Edit: January 11, 2016, 01:59:11 PM by RefuaFan »

Offline Work-for-ur-muny

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Re: Want to remain anonymous, when you win the powerball?
« Reply #105 on: January 11, 2016, 01:53:07 PM »

Not convinced.
Each individual ticket has 1 in 290 mm possibility of winning. Buying two tickets dosnt split the 290 in half.

(It's more like rubah deleisa kamon, not more chances. Just more options.)

All jmho
???
   1                     2
-------      =      -------
 29m               290m

?
?
?
« Last Edit: January 11, 2016, 03:06:22 PM by Work-for-ur-muny »

Offline yos9694

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Re: Want to remain anonymous, when you win the powerball?
« Reply #106 on: January 11, 2016, 01:59:08 PM »
   1                     2
-------      =      -------
 29m               290m

Rounded to 2dp, yes. Unrounded, no.

Offline yuneeq

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Re: Want to remain anonymous, when you win the powerball?
« Reply #107 on: January 11, 2016, 02:28:41 PM »
http://math.stackexchange.com/questions/1369659/if-i-buy-2-lottery-tickets-do-i-double-my-chance-of-winning

So I guess you're retracting?
Every answer says that this type of lottery you double your chances by buying 2 different tickets.

Offline elit

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Re: Want to remain anonymous, when you win the powerball?
« Reply #108 on: January 11, 2016, 02:30:40 PM »
So I guess you're retracting?
Every answer says that this type of lottery you double your chances by buying 2 different tickets.
Correct

Offline churnbabychurn

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Re: Want to remain anonymous, when you win the powerball?
« Reply #109 on: January 11, 2016, 02:43:18 PM »
One things a fact.
Buying two tickets doubles your chance of loosing

Online TimT

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Re: Want to remain anonymous, when you win the powerball?
« Reply #110 on: January 11, 2016, 02:44:07 PM »
One things a fact.
Buying two tickets doubles your chance of loosing
And 290M ?

Offline Zkpncs48

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Re: Want to remain anonymous, when you win the powerball?
« Reply #111 on: January 11, 2016, 02:44:40 PM »
   1                     2
-------      =      -------
 145m             290m
FTFY
« Last Edit: January 11, 2016, 02:52:15 PM by Zkpncs48 »

Offline Work-for-ur-muny

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Re: Want to remain anonymous, when you win the powerball?
« Reply #112 on: January 11, 2016, 03:07:01 PM »
FTFY
Right. My bad. So isn't that an indication that the cbc is right?

Offline Zkpncs48

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Re: Want to remain anonymous, when you win the powerball?
« Reply #113 on: January 11, 2016, 03:23:08 PM »
Right. My bad. So isn't that an indication that the cbc is right?
Not at all. It actually explains why he's wrong. I dont really have the patience to explain it though. Sorry

Offline David Smith

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Re: Want to remain anonymous, when you win the powerball?
« Reply #114 on: January 11, 2016, 03:31:50 PM »
All mathematical calculations aside, I think that buying 2 tickets doesn't make sense. Your chances are still so low, and the change in likelihood so insignificant, that it doesn't make sense to spend more money. The first ticket purchased I understand, that you want to have a ticket in the biggest lottery in history. I'm not sure what the second tickets adds.
My $.02.
Who do you think you are fooling? You think you are going to pull a quick one on your Creator? Good luck with that.
JTZ

Offline srulky

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Re: Want to remain anonymous, when you win the powerball?
« Reply #115 on: January 11, 2016, 03:37:13 PM »
When you win....

Offline Dan

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Re: Want to remain anonymous, when you win the powerball?
« Reply #116 on: January 11, 2016, 03:37:51 PM »
All mathematical calculations aside, I think that buying 2 tickets doesn't make sense. Your chances are still so low, and the change in likelihood so insignificant, that it doesn't make sense to spend more money. The first ticket purchased I understand, that you want to have a ticket in the biggest lottery in history. I'm not sure what the second tickets adds.
My $.02.

2nd ticket hurts as I explained earlier ;)
Save your time, I don't answer PM. Post it in the forum and a dedicated DDF'er will get back to you as soon as possible.

Offline David Smith

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Re: Want to remain anonymous, when you win the powerball?
« Reply #117 on: January 11, 2016, 03:39:33 PM »
2nd ticket hurts as I explained earlier ;)
You mean this?
20 cents each. Buying more than 1=katnus emunah ;)
Anyway, there are 57 other lottery threads, dunno why you picked this one for a pool.
Who do you think you are fooling? You think you are going to pull a quick one on your Creator? Good luck with that.
JTZ

Offline Luvtotravel

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Re: Want to remain anonymous, when you win the powerball?
« Reply #118 on: January 11, 2016, 11:26:20 PM »
didnt get email address yet
Don't wait for the perfect moment; take the moment and make it perfect.

Offline Naphtali

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Re: Want to remain anonymous, when you win the powerball?
« Reply #119 on: January 11, 2016, 11:30:16 PM »
didnt get email address yet

check inbox now.